Year 12 Complex Numbers: Powers of complex numbers

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Powers of full complex numbers combine everything from the earlier subtopics: multiplication, standard form, and the cycle of powers of i. Questions may involve squaring a complex number, cubing one, or simplifying expressions where the same complex factor appears repeatedly. The skill is not to invent a completely new method each time, but to use structure wisely. Sometimes direct expansion is best. Sometimes repeated multiplication with a previously simplified result is safer.

Rewrite every intermediate result in a+bi form before moving to the next power.

Subtopic 1: Squaring and cubing complex numbers

The first useful powers are squares and cubes. A square can often be handled with a direct binomial expansion, while a cube is often easier if you first simplify the square and then multiply once more. This avoids carrying too many unsimplified i terms at once.

Worked example 1

Problem: Simplify (2+i)2.
  1. Expand: (2+i)(2+i)=4+2i+2i+i2.
  2. Combine like terms: 4+4i+i2.
  3. Use i2=-1.
  4. The result is 3+4i.
Answer:(2+i)2=3+4i.

Subtopic 2: Building higher powers step by step

Higher powers often become easier if you reuse earlier simplifications. For example, if you need the cube of a complex number, first find the square in standard form, then multiply by the original factor once more. This reduces clutter and keeps the bookkeeping under control.

Worked example 2

Problem: Simplify (1+i)3.
  1. First square: (1+i)2=1+2i+i2=2i.
  2. Now multiply by (1+i) again: (1+i)3=(2i)(1+i).
  3. Expand: 2i+2i2.
  4. Use i2=-1: 2i-2.
  5. Write in standard form: -2+2i.
Answer:(1+i)3=-2+2i.

Subtopic 3: Using the power of i cycle inside larger powers

Sometimes a complex power simplifies into a combination of ordinary coefficients and powers of i. Once that happens, the cycle from the previous subtopic becomes the main simplification tool. The key is to avoid leaving large powers unsimplified for too long. Collapse them when they appear, then continue in standard form.

Worked example 3

Problem: Simplify (2i)5.
  1. Separate the numerical and imaginary parts: (2i)5=25i5.
  2. Compute the numerical power: 25=32.
  3. Reduce i5 using the cycle: i5=i.
  4. So the result is 32i.
Answer:(2i)5=32i.

Why standard form must keep returning

Large powers can become messy very quickly if you do not reset the expression after each major step. Writing every intermediate result as a+bi is not just a presentation choice. It is a control mechanism. It lets you see what part is real, what part is imaginary, and where the next multiplication needs to begin. In practice, this is what separates a short correct solution from a long confused one.

Common traps

  • Expanding too far without simplifying intermediate powers of i.
  • Forgetting to return each stage to standard form.
  • Making arithmetic mistakes in repeated multiplication.
  • Ignoring an easier structure such as separating a scalar from a power of i.

Revision focus

In revision, practise building powers in stages. Square first, simplify, then multiply again if needed. This is especially effective for cubes and fourth powers. It keeps the algebra modular and makes errors easier to locate.

Another useful habit is to ask whether the expression can be split into a simple scalar part and a pure power of i. If that is possible, the calculation often shortens dramatically and becomes much cleaner.

Practice links